已关闭问题 (普通问题)
GSM的CBC配置的物理信道上,PCH与AGCH所占用的块的总数为

GSMCBC配置的物理信道上,PCHAGCH所占用的块的总数为3,请问具体计算过程

非常感谢!

提问者: guoxinchao  提问时间: 2015-03-19    
 

更多 PCH AGCH GSM CBC 信道 物理信道 AGC 配置 C_C 相关问题
问题答案 ( 1 )

这问题问的一点也不严谨,如果CBCH信道和SDCCH信道使用相同的信道,如果配置CBCH(SDCCH/4)的话,CBCH占用时隙0,本来PCH和AGCH占用0,2,4,6 4个信道,那么这时候只剩下3个了

Channel                                   Sub‑                 Direction                 Allowable                Allowable                        Burst       Repeat                     Interleaved block
designation                              channel                                            timeslot                   RF channel                      type         length in                  TDMA frame
                                                number                                            assignments             assignments                                     TDMA frames         mapping

FCCH                                                                        D                    0                              C0                                    FB                    51                            B0(0),B1(10),B2(20),B3(30),B4(40)

SCH                                                                          D                    0                              C0                                    SB                    51                            B0(1),B1(11),B2(21),B3(31),B4(41)

BCCH Norm                                                              D                    0,2,4,6                     C0                                    NB                   51                   B(2..5)

BCCH Ext                                                                 D                    0,2,4,6                     C0                                    NB                   51                   B(6...9)

PCH                                                                          D                    0,2,4,6                     C0                                    NB                   51                                B0(6..9),B1(12..15),B2(16..19)
AGCH                                                                                                                                                                                                                             B3(22..25),B4(26..29),B5(32..35),
                                                                                                                                                                                                                                         B6(36..39),B7(42..45),B8(46..49)

NCH                                                                          D                    0                              C0                                    NB                   51                                B0(6..9),B1(12..15),B2(16..19)
                                                                                                                                                                                                                                        B3(22..25),B4(26..29),B5(32..35),
                                                                                                                                                                                                                                B6(36..39)

RACH                                                                       U                    0,2,4,6                     C0                                    AB                   51                                       B0(0),B1(1)..B50(50)

CBCH(SDCCH/4)                                                      D                    0                              C0                                    NB                   51                   B(32..35)

CBCH(SDCCH/8)                                                      D                    0 ... 3                       C0 ... Cn                           NB                   51                   B(8..11)

SDCCH/4                                        0                        D                    0                              C0                                   NB1                  51                   B(22..25)
                                                                                 U                                                                                                                                            B(37..40)
                                                       1                        D                                                                                                                                            B(26..29)
                                                                                 U                                                                                                                                            B(41..44)
                                                       2                        D                                                                                                                                            B(32..35)
                                                                                 U                                                                                                                                            B(47..50)
                                                       3                        D                                                                                                                                            B(36..39)
                                                                                 U                                                                                                                                            B(0..3)

SACCH/C4                                      0                        D                    0                              C0                                   NB3                 102                  B(42..45)
                                                                                 U                                                                                                                                            B(57..60)
                                                       1                        D                                                                                                                                            B(46..49)
                                                                                 U                                                                                                                                            B(61..64)
                                                       2                        D                                                                                                                                            B(93..96)
                                                                                 U                                                                                                                                            B(6..9)
                                                       3                        D                                                                                                                                            B(97..100)
                                                                                 U                                                                                                                                            B(10..13)




回答者: wwwmscbsccom     回答时间:2015-03-20 08:57    

2        1         评价该回答(2)
感谢您的答复,可惜看不懂
呵呵
guoxinchao  2015-03-20 10:13 

那就没办法啦,请采纳吧!这些都是协议规定的,其实没有为什么!
wwwmscbsccom  2015-03-20 21:44 


中国通信人才网 | 江苏通信人才网 | 山东通信人才网 | 武汉通信人才网 | 浙江通信人才网 | 湖南通信人才网
南京嘉环科技股份有限公司 聘:网优LTE中级工程师
需求人数:3 人 地点:银川市
重庆永鹏网络科技股份有限公司 聘:广西百色联通中高级人员
需求人数:1 人 地点:百色市
合肥讯诚通信科技有限公司 聘:LTE中高级后台网优(青海)
需求人数:5 人 地点:青海省
杭州东信网络技术有限公司 聘:福建4/5G高级人员
需求人数:3 人 地点:漳州市
普天信息工程设计服务有限公司 聘:高铁优化工程师
需求人数:10 人 地点:福建省
西安长河通讯有限责任公司 聘:中兴传输类IPRAN工程师
需求人数:5 人 地点:海外
北京电旗通讯技术股份有限公司 聘:网优实习生通信应届生(云南)
需求人数:1 人 地点:昆明市,思茅市,昭通市
中通国脉通信股份有限公司 聘:数据通信工程师-吉林省
需求人数:5 人 地点:吉林省
南京格安信息系统有限责任公司 聘:IMC数通接入工程师
需求人数:2 人 地点:天津市
四川省世源恒达科技有限公司 聘:LTE系统网优工程师
需求人数:3 人 地点:六盘水市,铜仁地区,毕节地区
热点问题
赞助商链接


联系我们 - 问通信专家 Powered by MSCBSC 移动通信网  © 2006 -