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(普通问题)
为什么在TDD-LTE中一个上行子帧可以包含多个PRACH信道？而在FDD中却不可以
为什么在TDD-LTE中一个上行子帧可以包含多个PRACH信道？而在FDD中一个上行子帧只能包含一个PRACH？
提问者:
• 如何做PRACH RSIs规划以及PCI规划 2019-11-18
• 决定NR中PRACH带宽的因素？ 2019-09-18
• ue不断上发pRACH:msg1（ra）的原因？ 2019-09-09
• NPRACH什么意思 2019-04-22
• PRACH资源在一定程度上反映设备负荷情况，为设备是否需要扩容提供依据 2017-07-09
• 高铁规划pci和pRACH什么原则 有规划表吗？ 2017-06-11
• LTE向多个站间目标小区切换失败 2017-05-23
• 诺基亚PRACH参数 2017-04-25
• 决定NR中PRACH带宽的因素？ 2019-09-18
• ue不断上发pRACH:msg1（ra）的原因？ 2019-09-09
• NPRACH什么意思 2019-04-22
• PRACH资源在一定程度上反映设备负荷情况，为设备是否需要扩容提供依据 2017-07-09
• 高铁规划pci和pRACH什么原则 有规划表吗？ 2017-06-11
• LTE向多个站间目标小区切换失败 2017-05-23
• 诺基亚PRACH参数 2017-04-25
问题答案
( 2 )
没有啊，参看下列信息：
Table 5.7.1-2: Frame structure type 1 random access configuration for preamble formats 0-3.
Table 5.7.1 -3: Frame structure type 2 random access configurations for preamble formats 0-4.
Table 5.7.1-2: Frame structure type 1 random access configuration for preamble formats 0-3.
|
PRACH Configuration Index |
Preamble Format |
System frame number |
Subframe number |
PRACH Configuration Index |
Preamble Format |
System frame number |
Subframe number |
|
0 |
0 |
Even |
1 |
32 |
2 |
Even |
1 |
|
1 |
0 |
Even |
4 |
33 |
2 |
Even |
4 |
|
2 |
0 |
Even |
7 |
34 |
2 |
Even |
7 |
|
3 |
0 |
Any |
1 |
35 |
2 |
Any |
1 |
|
4 |
0 |
Any |
4 |
36 |
2 |
Any |
4 |
|
5 |
0 |
Any |
7 |
37 |
2 |
Any |
7 |
|
6 |
0 |
Any |
1, 6 |
38 |
2 |
Any |
1, 6 |
|
7 |
0 |
Any |
2 ,7 |
39 |
2 |
Any |
2 ,7 |
|
8 |
0 |
Any |
3, 8 |
40 |
2 |
Any |
3, 8 |
|
9 |
0 |
Any |
1, 4, 7 |
41 |
2 |
Any |
1, 4, 7 |
|
10 |
0 |
Any |
2, 5, 8 |
42 |
2 |
Any |
2, 5, 8 |
|
11 |
0 |
Any |
3, 6, 9 |
43 |
2 |
Any |
3, 6, 9 |
|
12 |
0 |
Any |
0, 2, 4, 6, 8 |
44 |
2 |
Any |
0, 2, 4, 6, 8 |
|
13 |
0 |
Any |
1, 3, 5, 7, 9 |
45 |
2 |
Any |
1, 3, 5, 7, 9 |
|
14 |
0 |
Any |
0, 1, 2, 3, 4, 5, 6, 7, 8, 9 |
46 |
N/A |
N/A |
N/A |
|
15 |
0 |
Even |
9 |
47 |
2 |
Even |
9 |
|
16 |
1 |
Even |
1 |
48 |
3 |
Even |
1 |
|
17 |
1 |
Even |
4 |
49 |
3 |
Even |
4 |
|
18 |
1 |
Even |
7 |
50 |
3 |
Even |
7 |
|
19 |
1 |
Any |
1 |
51 |
3 |
Any |
1 |
|
20 |
1 |
Any |
4 |
52 |
3 |
Any |
4 |
|
21 |
1 |
Any |
7 |
53 |
3 |
Any |
7 |
|
22 |
1 |
Any |
1, 6 |
54 |
3 |
Any |
1, 6 |
|
23 |
1 |
Any |
2 ,7 |
55 |
3 |
Any |
2 ,7 |
|
24 |
1 |
Any |
3, 8 |
56 |
3 |
Any |
3, 8 |
|
25 |
1 |
Any |
1, 4, 7 |
57 |
3 |
Any |
1, 4, 7 |
|
26 |
1 |
Any |
2, 5, 8 |
58 |
3 |
Any |
2, 5, 8 |
|
27 |
1 |
Any |
3, 6, 9 |
59 |
3 |
Any |
3, 6, 9 |
|
28 |
1 |
Any |
0, 2, 4, 6, 8 |
60 |
N/A |
N/A |
N/A |
|
29 |
1 |
Any |
1, 3, 5, 7, 9 |
61 |
N/A |
N/A |
N/A |
|
30 |
N/A |
N/A |
N/A |
62 |
N/A |
N/A |
N/A |
|
31 |
1 |
Even |
9 |
63 |
3 |
Even |
9 |
|
PRACH configuration Index |
Preamble Format |
Density Per 10 ms |
Version |
PRACH configuration Index |
Preamble Format |
Density Per 10 ms |
Version |
|
0 |
0 |
0.5 |
0 |
32 |
2 |
0.5 |
2 |
|
1 |
0 |
0.5 |
1 |
33 |
2 |
1 |
0 |
|
2 |
0 |
0.5 |
2 |
34 |
2 |
1 |
1 |
|
3 |
0 |
1 |
0 |
35 |
2 |
2 |
0 |
|
4 |
0 |
1 |
1 |
36 |
2 |
3 |
0 |
|
5 |
0 |
1 |
2 |
37 |
2 |
4 |
0 |
|
6 |
0 |
2 |
0 |
38 |
2 |
5 |
0 |
|
7 |
0 |
2 |
1 |
39 |
2 |
6 |
0 |
|
8 |
0 |
2 |
2 |
40 |
3 |
0.5 |
0 |
|
9 |
0 |
3 |
0 |
41 |
3 |
0.5 |
1 |
|
10 |
0 |
3 |
1 |
42 |
3 |
0.5 |
2 |
|
11 |
0 |
3 |
2 |
43 |
3 |
1 |
0 |
|
12 |
0 |
4 |
0 |
44 |
3 |
1 |
1 |
|
13 |
0 |
4 |
1 |
45 |
3 |
2 |
0 |
|
14 |
0 |
4 |
2 |
46 |
3 |
3 |
0 |
|
15 |
0 |
5 |
0 |
47 |
3 |
4 |
0 |
|
16 |
0 |
5 |
1 |
48 |
4 |
0.5 |
0 |
|
17 |
0 |
5 |
2 |
49 |
4 |
0.5 |
1 |
|
18 |
0 |
6 |
0 |
50 |
4 |
0.5 |
2 |
|
19 |
0 |
6 |
1 |
51 |
4 |
1 |
0 |
|
20 |
1 |
0.5 |
0 |
52 |
4 |
1 |
1 |
|
21 |
1 |
0.5 |
1 |
53 |
4 |
2 |
0 |
|
22 |
1 |
0.5 |
2 |
54 |
4 |
3 |
0 |
|
23 |
1 |
1 |
0 |
55 |
4 |
4 |
0 |
|
24 |
1 |
1 |
1 |
56 |
4 |
5 |
0 |
|
25 |
1 |
2 |
0 |
57 |
4 |
6 |
0 |
|
26 |
1 |
3 |
0 |
58 |
N/A |
N/A |
N/A |
|
27 |
1 |
4 |
0 |
59 |
N/A |
N/A |
N/A |
|
28 |
1 |
5 |
0 |
60 |
N/A |
N/A |
N/A |
|
29 |
1 |
6 |
0 |
61 |
N/A |
N/A |
N/A |
|
30 |
2 |
0.5 |
0 |
62 |
N/A |
N/A |
N/A |
|
31 |
2 |
0.5 |
1 |
63 |
N/A |
N/A |
N/A |
回答者：
ebrain68
回答时间：2014-05-13 15:09
9
9
没有看太明白，可以解释下吗
春上秋下0712 2014-05-13 15:36
Frame structure type 1是FDD的frame结构，你看表里的subframe number一栏是在一个radio frame中可能承载prach的subframe的号码么
ebrain68 2014-05-13 22:51
由它们的双工方式决定的，TDD上下行共用频段，传输能力较弱，为保证容量，即需要发送密度较高时，需在同一个上行子帧内配置多个PRACH。
回答者：
lidashu414
回答时间：2014-05-13 16:15
9
8
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